8[3-(4+4x)]=-10+2(1-18x)

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Solution for 8[3-(4+4x)]=-10+2(1-18x) equation:


Simplifying
8[3 + -1(4 + 4x)] = -10 + 2(1 + -18x)
8[3 + (4 * -1 + 4x * -1)] = -10 + 2(1 + -18x)
8[3 + (-4 + -4x)] = -10 + 2(1 + -18x)

Combine like terms: 3 + -4 = -1
8[-1 + -4x] = -10 + 2(1 + -18x)
[-1 * 8 + -4x * 8] = -10 + 2(1 + -18x)
[-8 + -32x] = -10 + 2(1 + -18x)
-8 + -32x = -10 + (1 * 2 + -18x * 2)
-8 + -32x = -10 + (2 + -36x)

Combine like terms: -10 + 2 = -8
-8 + -32x = -8 + -36x

Add '8' to each side of the equation.
-8 + 8 + -32x = -8 + 8 + -36x

Combine like terms: -8 + 8 = 0
0 + -32x = -8 + 8 + -36x
-32x = -8 + 8 + -36x

Combine like terms: -8 + 8 = 0
-32x = 0 + -36x
-32x = -36x

Solving
-32x = -36x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '36x' to each side of the equation.
-32x + 36x = -36x + 36x

Combine like terms: -32x + 36x = 4x
4x = -36x + 36x

Combine like terms: -36x + 36x = 0
4x = 0

Divide each side by '4'.
x = 0

Simplifying
x = 0

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